III. 3) The Substraction

of the Intervals

from each other

 
zurück: inhalt
by dr. fazli arslan
ihre meinung/ fragen zu dieser seite? (forum)
kontakt
newsletter
home
start: 09 january 2007, up-date: 09 january 2007
As we want to subtract a small interval from a big interval, if the ratio to be subtracted is intended to leave at the high in pitch side, firstly the numerator of the big side and the denominator of the small side are multiplied and then the denominators are multiplied by each other. Let's subtract 3/2 from 4/3. It is 3x3=9, 3x2=6. We multiply 2 by 4 for the vasat number. We get the numbers of 9, 8, and 6 which is a process when we want 9/8 to leave at the high in pitch side. Here, 9/8 is at the high in pitch and 4/3 ratio which exists between 8 and 6 is left at the low in pitch side. If we want to leave the ratio to be obtained at the low in pitch side, in this case we multiply the denominators by each other. The result is 12. As it is seen, the ratio of 9/8 which is between the numbers of 12, 9, 8 is at the low in pitch side. (7)